The material of electric heating tube is mainly selected according to the following aspects:

The material of electric heating tube is mainly selected according to the following aspects:

　　 One, working temperature

　　 The working temperature is about 200-300 degrees, and the material is stainless steel 304.

　　The working temperature is about 400-500 degrees, and the material of stainless steel 321 is used.

　　 The working temperature is around 600-700 degrees, using stainless steel 310S material.

　　 The working temperature is around 800-900 degrees, and the material is made of Ingle.

　　 2. Heating medium

　　Tap water: made of stainless steel 304;

　　Oil: stainless steel 304 material or iron material.

　　 3. Whether corrosive

　　 Heating weakly acidic and weakly alkaline liquids: made of corrosion-resistant stainless steel 316L.

Heating strong acid and strong alkaline liquids: refer to the selection table of liquid electric heaters (stainless steel 316 + electrostatic anti-corrosion coating, generally any acid and alkaline liquids can withstand, the power per meter is generally set to about 2KW, slightly larger can.)

What material is the best electric heating tube?

　　 is mainly divided into: stainless steel 201, stainless steel 304, stainless steel 321, stainless steel 310s, stainless steel 316, Ingle Material, etc. Each material has its own characteristics, so only by choosing the right material can it be regarded as a good electric heating tube material.

lectric heating tube power calculation:

　　1, empirical calculation-P = actual current / 1.5 = 78 / 1.5 = 52 kilowatts;
2. Formula calculation—P=IU, P=√3UxIx, where Ux is the line voltage, Ix is the line current, P=√3UxIx=√3×380×78≈52 kW. 11 Electric power P is equal to the square of current into resistance P=IIR (General formula) Electric power is equal to current multiplied by voltage P=UI=380V×78A=29640W4

Calculation formula for surface load of electric heating tube:

　　 Electric heating tube surface load (w/cm2 (watt density)) = W (electric heating tube power)/D × π × L(cm)
　　 Among them, D = the diameter of the heating tube; (π = 3.1416); (L = the length of the heating part);

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